x^2-0.6x=5

Solution for x^2-0.6x=5 equation:

x^2-0.6x=5

We move all terms to the left:

x^2-0.6x-(5)=0

a = 1; b = -0.6; c = -5;
Δ = b2-4ac
Δ = -0.62-4·1·(-5)
Δ = 20.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.6)-\sqrt{20.36}}{2*1}=\frac{0.6-\sqrt{20.36}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.6)+\sqrt{20.36}}{2*1}=\frac{0.6+\sqrt{20.36}}{2}
$